What is the derivative of-x^2+3x+a ?

The derivative of-x^2+3x+a is -2x+3

What is the first derivative of-x^2+3x+a ?

The first derivative of-x^2+3x+a is -2x+3

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derivative of

- x^{2} + 3 x + a

- 2 x + 3

Solution steps

\frac{d}{d x} (- x^{2} + 3 x + a)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (x^{2}) + \frac{d}{d x} (3 x) + \frac{d a}{d x}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (3 x) = 3

\frac{d a}{d x} = 0

= - 2 x + 3 + 0

Simplify

= - 2 x + 3

x \to 0 lim (2 x^{2} - 2 x - 12)

\int_{- 1}^{1} x^{2} + y^{2} d x

\int sec^{2} (x) tan^{6} (x) d x

\frac{\partial}{\partial y} (x^{2} e^{5 y})

F (s) = \frac{7}{4 s - 12}

What is the derivative of-x^2+3x+a ?
The derivative of-x^2+3x+a is -2x+3
What is the first derivative of-x^2+3x+a ?
The first derivative of-x^2+3x+a is -2x+3