What is the integral from 0 to 1 of 1-\sqrt[4]{x} ?

The integral from 0 to 1 of 1-\sqrt[4]{x} is 1/5

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integral from 0 to 1 of 1-\sqrt[4]{x}

\int_{0}^{1} 1 - 4 x d x

\frac{1}{5}

Decimal

0.2

Solution steps

\int_{0}^{1} 1 - 4 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} 1 d x - \int_{0}^{1} 4 x d x

\int_{0}^{1} 1 d x = 1

\int_{0}^{1} 4 x d x = \frac{4}{5}

= 1 - \frac{4}{5}

Simplify

1 - \frac{4}{5} : \frac{1}{5}

= \frac{1}{5}

\int \frac{16 + x ^{2}}{2 x ^{4}} d x

\int (2 x^{2} - 1)^{\frac{1}{2}} d x

f (x) = ln (cos (x))

\frac{d}{d x} (ln (x^{2} + 2))

n = 1 \sum \infty (x + 1)^{n}

What is the integral from 0 to 1 of 1-\sqrt[4]{x} ?
The integral from 0 to 1 of 1-\sqrt[4]{x} is 1/5