What is the integral of (3x+4)/(x^2+3x+2) ?

The integral of (3x+4)/(x^2+3x+2) is ln|x+1|+2ln|x+2|+C

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integral of (3x+4)/(x^2+3x+2)

\int \frac{3 x + 4}{x ^{2} + 3 x + 2} d x

ln ∣ x + 1 ∣ + 2 ln ∣ x + 2 ∣ + C

Solution steps

\int \frac{3 x + 4}{x ^{2} + 3 x + 2} d x

Take the partial fraction of

\frac{3 x + 4}{x ^{2} + 3 x + 2} : \frac{1}{x + 1} + \frac{2}{x + 2}

= \int \frac{1}{x + 1} + \frac{2}{x + 2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{1}{x + 1} d x + \int \frac{2}{x + 2} d x

\int \frac{1}{x + 1} d x = ln ∣ x + 1 ∣

\int \frac{2}{x + 2} d x = 2 ln ∣ x + 2 ∣

= ln ∣ x + 1 ∣ + 2 ln ∣ x + 2 ∣

Add a constant to the solution

= ln ∣ x + 1 ∣ + 2 ln ∣ x + 2 ∣ + C

\int (4 x - x^{2}) d x

\frac{\partial}{\partial x} (- 2 sin (2 x))

arcsec (3 x)

y^{^{'}} = x^{2} y

4 t h \frac{1}{x - 5}

What is the integral of (3x+4)/(x^2+3x+2) ?
The integral of (3x+4)/(x^2+3x+2) is ln|x+1|+2ln|x+2|+C