What is the integral of \sqrt[3]{2x^2} ?

The integral of \sqrt[3]{2x^2} is \sqrt[3]{2} 3/5 x^{5/3}+C

Popular >

integral of \sqrt[3]{2x^2}

\int 3 2 x^{2} d x

32 \frac{3}{5} x^{\frac{5}{3}} + C

Solution steps

\int 3 2 x^{2} d x

Apply radical rule:

n ab = n a n b,

assuming

a \geq 0, b \geq 0

= \int 32 3 x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 32 \cdot \int 3 x^{2} d x

3 x^{2} = x^{\frac{2}{3}},

assuming

x \geq 0

= 32 \cdot \int x^{\frac{2}{3}} d x

Apply the Power Rule

: \frac{3}{5} x^{\frac{5}{3}}

= 32 \frac{3}{5} x^{\frac{5}{3}}

Add a constant to the solution

= 32 \frac{3}{5} x^{\frac{5}{3}} + C

\frac{d y}{d x} = \frac{1}{2} (k x^{- 1} - x)

x \to - 4 lim (- \frac{2 x ^{2} - 17}{3})

\int 5 y^{2} d y

\frac{\partial}{\partial x} (2 cos (x) cos (y))

h \to 0 lim (\frac{13 h}{h})

What is the integral of \sqrt[3]{2x^2} ?
The integral of \sqrt[3]{2x^2} is \sqrt[3]{2} 3/5 x^{5/3}+C