What is (\partial}{\partial x}(\frac{x^2y^2)/2) ?

The answer to (\partial}{\partial x}(\frac{x^2y^2)/2) is xy^2

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(\partial}{\partial x}(\frac{x^2y^2)/2)

\frac{\partial}{\partial x} (\frac{x ^{2} y ^{2}}{2})

x y^{2}

Solution steps

\frac{\partial}{\partial x} (\frac{x ^{2} y ^{2}}{2})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{y ^{2}}{2} \frac{\partial}{\partial x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{y ^{2}}{2} \cdot 2 x^{2 - 1}

Simplify

\frac{y ^{2}}{2} \cdot 2 x^{2 - 1} : x y^{2}

= x y^{2}

n = 1 \sum \infty n^{- s i n (2)}

(cos^{2} (θ))^{^{'}}

\frac{1}{1 - x}

\frac{d}{d x} (\frac{8 x}{3 - tan ( x )})

f (x) = 7 x + 2

What is (\partial}{\partial x}(\frac{x^2y^2)/2) ?
The answer to (\partial}{\partial x}(\frac{x^2y^2)/2) is xy^2