What is the derivative of (8x/(3-tan(x))) ?

The derivative of (8x/(3-tan(x))) is (8(3-tan(x)+xsec^2(x)))/((3-tan(x))^2)

What is the first derivative of (8x/(3-tan(x))) ?

The first derivative of (8x/(3-tan(x))) is (8(3-tan(x)+xsec^2(x)))/((3-tan(x))^2)

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\frac{d}{d x} (\frac{8 x}{3 - tan ( x )})

\frac{8 ( 3 - tan ( x ) + x sec ^{2} ( x ) )}{( 3 - tan ( x ) ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{8 x}{3 - tan ( x )})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 \frac{d}{d x} (\frac{x}{3 - tan ( x )})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 8 \cdot \frac{\frac{d x}{d x} ( 3 - tan ( x ) ) - \frac{d}{d x} ( 3 - tan ( x ) ) x}{( 3 - tan ( x ) ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} (3 - tan (x)) = - sec^{2} (x)

= 8 \cdot \frac{1 \cdot ( 3 - tan ( x ) ) - ( - sec ^{2} ( x ) ) x}{( 3 - tan ( x ) ) ^{2}}

Simplify

8 \cdot \frac{1 \cdot ( 3 - tan ( x ) ) - ( - sec ^{2} ( x ) ) x}{( 3 - tan ( x ) ) ^{2}} : \frac{8 ( 3 - tan ( x ) + x sec ^{2} ( x ) )}{( 3 - tan ( x ) ) ^{2}}

= \frac{8 ( 3 - tan ( x ) + x sec ^{2} ( x ) )}{( 3 - tan ( x ) ) ^{2}}

f (x) = 7 x + 2

\frac{d y}{d x} = \frac{( x - 3 )}{2 - y}

\frac{d}{d x} (- x^{2})

\frac{d}{d x} (sec^{2} (x) tan (x))

\frac{\partial}{\partial x} (ln (x + 7 y + 2 z))

What is the derivative of (8x/(3-tan(x))) ?
The derivative of (8x/(3-tan(x))) is (8(3-tan(x)+xsec^2(x)))/((3-tan(x))^2)
What is the first derivative of (8x/(3-tan(x))) ?
The first derivative of (8x/(3-tan(x))) is (8(3-tan(x)+xsec^2(x)))/((3-tan(x))^2)