What is the derivative of x^2+4x-3 ?

The derivative of x^2+4x-3 is 2x+4

What is the first derivative of x^2+4x-3 ?

The first derivative of x^2+4x-3 is 2x+4

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derivative of

x^{2} + 4 x - 3

2 x + 4

Solution steps

\frac{d}{d x} (x^{2} + 4 x - 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (4 x) - \frac{d}{d x} (3)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (3) = 0

= 2 x + 4 - 0

Simplify

= 2 x + 4

3.5 x - 2 x^{2}

\int \frac{1 - 2 x}{x + 1} d x

\frac{d}{d r} (e^{r} + r^{e})

\int cot (24 x) d x

13 sin (x), 13 cos (x), 0, π

What is the derivative of x^2+4x-3 ?
The derivative of x^2+4x-3 is 2x+4
What is the first derivative of x^2+4x-3 ?
The first derivative of x^2+4x-3 is 2x+4