What is the limit as x approaches 0 of 1-2sin^2(x/2) ?

The limit as x approaches 0 of 1-2sin^2(x/2) is 1

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limit as x approaches 0 of 1-2sin^2(x/2)

x \to 0 lim (1 - 2 sin^{2} (\frac{x}{2}))

1

Solution steps

x \to 0 lim (1 - 2 sin^{2} (\frac{x}{2}))

Plug in the value

x = 0

= 1 - 2 sin^{2} (\frac{0}{2})

Simplify

1 - 2 sin^{2} (\frac{0}{2}) : 1

= 1

x \to 1 + lim (2 x - 2 - 2)

\int \frac{6 x + 5}{3 x ^{2} + 5 x} d x

\int_{3}^{5} \frac{1}{x ^{2} - 9} d x

f (x) = (x^{3} - 10 x) (3 x^{2} + 4 x)

y = x^{2} ln (x), y = 4 ln (x)

What is the limit as x approaches 0 of 1-2sin^2(x/2) ?
The limit as x approaches 0 of 1-2sin^2(x/2) is 1