What is the derivative of (x^2-1^2) ?

The derivative of (x^2-1^2) is 4x(x^2-1)

What is the first derivative of (x^2-1^2) ?

The first derivative of (x^2-1^2) is 4x(x^2-1)

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\frac{d}{d x} ((x^{2} - 1)^{2})

4 x (x^{2} - 1)

Solution steps

\frac{d}{d x} ((x^{2} - 1)^{2})

Apply the chain rule:

2 (x^{2} - 1) \frac{d}{d x} (x^{2} - 1)

= 2 (x^{2} - 1) \frac{d}{d x} (x^{2} - 1)

\frac{d}{d x} (x^{2} - 1) = 2 x

= 2 (x^{2} - 1) \cdot 2 x

Simplify

= 4 x (x^{2} - 1)

y = \frac{5}{( 4 x ) ^{- 2}}

\frac{\partial}{\partial x} (sec (y))

\int e^{2 x} cos (\frac{x}{4}) d x

\frac{d}{d x} (\frac{x}{2 + x})

\frac{1}{( y ^{2} - 3 y + 2 )} y^{^{'}} = \frac{1}{x}

What is the derivative of (x^2-1^2) ?
The derivative of (x^2-1^2) is 4x(x^2-1)
What is the first derivative of (x^2-1^2) ?
The first derivative of (x^2-1^2) is 4x(x^2-1)