What is the solution for (dy)/(dx)+3y=10,y(0)=20 ?

The solution for (dy)/(dx)+3y=10,y(0)=20 is y= 10/3+(50)/(3e^{3x)}

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(dy)/(dx)+3y=10,y(0)=20

\frac{d y}{d x} + 3 y = 10, y (0) = 20

y = \frac{10}{3} + \frac{50}{3 e ^{3 x}}

Solution steps

\frac{d y}{d x} + 3 y = 10

Solve linear ODE:

y = \frac{10}{3} + \frac{50}{3 e ^{3 x}}

y = \frac{10}{3} + \frac{50}{3 e ^{3 x}}

x y = 24, 2 x^{2} - y^{2} + 4 = 0

\frac{d y}{d x} = \frac{x ^{2}}{10 y} - \frac{2 x}{5 y}

\frac{4}{3} π r^{3}

\frac{s - s}{s ^{2}}

y = 3 - x^{2}, y = - 1

What is the solution for (dy)/(dx)+3y=10,y(0)=20 ?
The solution for (dy)/(dx)+3y=10,y(0)=20 is y= 10/3+(50)/(3e^{3x)}