What is the integral from 0 to 1 of arctan(1) ?

The integral from 0 to 1 of arctan(1) is pi/4

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integral from 0 to 1 of arctan(1)

\int_{0}^{1} arctan (1) d x

\frac{π}{4}

Decimal

0.78539 \dots

Solution steps

\int_{0}^{1} arctan (1) d x

Integral of a constant:

\int a d x = a x

= [arctan (1) x]_{0}^{1}

Use the following trivial identity:

arctan (1) = \frac{π}{4}

x 0 \frac{3}{3} 13 arctan (x) 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} arctan (x) 0^{\circ} 3 0^{\circ} 4 5^{\circ} 6 0^{\circ}

= [\frac{π}{4} x]_{0}^{1}

Compute the boundaries:

\frac{π}{4}

= \frac{π}{4}

\frac{d}{d x} (e^{s i n (x)} - 1)

\int_{3}^{13} x d x

\int sin^{5} (x) cos^{5} (x) d x

x \to - 9 - lim (x^{2} - 81)

\int 2 x^{2} cos (m x) d x

What is the integral from 0 to 1 of arctan(1) ?
The integral from 0 to 1 of arctan(1) is pi/4