What is the sum from n=7 to infinity of 1/(6^n) ?

The sum from n=7 to infinity of 1/(6^n) is converges

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sum from n=7 to infinity of 1/(6^n)

n = 7 \sum \infty \frac{1}{6 ^{n}}

converges

Solution steps

n = 7 \sum \infty \frac{1}{6 ^{n}}

Apply Series Ratio Test:

converges

= converges

x \to 0 lim (\frac{\frac{1}{x - 1} - 1}{x})

\int_{0}^{20} x 20 - x d x

\int \frac{e ^{x}}{4} d x

f (x) = \frac{2}{x}, (5, \frac{2}{5})

y^{^{''}} + 12 y^{^{'}} + 35 y = 0

What is the sum from n=7 to infinity of 1/(6^n) ?
The sum from n=7 to infinity of 1/(6^n) is converges