What is the solution for y^{''}+12y^'+35y=0 ?

The solution for y^{''}+12y^'+35y=0 is y=c_{1}e^{-5t}+c_{2}e^{-7t}

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y^{''}+12y^'+35y=0

y^{^{''}} + 12 y^{^{'}} + 35 y = 0

y = c_{1} e^{- 5 t} + c_{2} e^{- 7 t}

Solution steps

y^{''} (t) + 12 y^{'} (t) + 35 y = 0

Solve linear ODE:

y = c_{1} e^{- 5 t} + c_{2} e^{- 7 t}

y = c_{1} e^{- 5 t} + c_{2} e^{- 7 t}

x \to 0 lim (\frac{4 - x}{x ^{2}})

\frac{5 ^{x^{3}}}{4 x ^{2}}

y = ln (x - 9)

\int_{0}^{1} \frac{2 x}{1 + x ^{2}} d x

\frac{d ^{2}}{d x ^{2}} (2 x^{3} - x)

What is the solution for y^{''}+12y^'+35y=0 ?
The solution for y^{''}+12y^'+35y=0 is y=c_{1}e^{-5t}+c_{2}e^{-7t}