What is the derivative of 6arctan(x) ?

The derivative of 6arctan(x) is 6/(x^2+1)

What is the first derivative of 6arctan(x) ?

The first derivative of 6arctan(x) is 6/(x^2+1)

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\frac{d}{d x} (6 arctan (x))

\frac{6}{x ^{2} + 1}

Solution steps

\frac{d}{d x} (6 arctan (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 6 \frac{d}{d x} (arctan (x))

Apply the common derivative:

\frac{d}{d x} (arctan (x)) = \frac{1}{x ^{2} + 1}

= 6 \cdot \frac{1}{x ^{2} + 1}

Simplify

6 \cdot \frac{1}{x ^{2} + 1} : \frac{6}{x ^{2} + 1}

= \frac{6}{x ^{2} + 1}

\int \frac{13 - 13 x}{1 - x} d x

\frac{d}{d x} (\frac{2}{x} - \frac{1}{x ^{2}})

2 4 - y

\int \frac{1}{x ^{2} - a ^{2}} d x

cos (x + y)

What is the derivative of 6arctan(x) ?
The derivative of 6arctan(x) is 6/(x^2+1)
What is the first derivative of 6arctan(x) ?
The first derivative of 6arctan(x) is 6/(x^2+1)