What is the limit as x approaches 0+of ln(0.1) ?

The limit as x approaches 0+of ln(0.1) is -2.30258…

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limit as x approaches 0+of ln(0.1)

x \to 0 + lim (ln (0.1))

- 2.30258 \dots

Solution steps

x \to 0 + lim (ln (0.1))

x \to a lim c = c

= ln (0.1)

Refine to a decimal form

= - 2.30258 \dots

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What is the limit as x approaches 0+of ln(0.1) ?
The limit as x approaches 0+of ln(0.1) is -2.30258…