What is (\partial)/(\partial y)(e^{x^2}-y) ?

The answer to (\partial)/(\partial y)(e^{x^2}-y) is -1

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(\partial)/(\partial y)(e^{x^2}-y)

\frac{\partial}{\partial y} (e^{x^{2}} - y)

- 1

Solution steps

\frac{\partial}{\partial y} (e^{x^{2}} - y)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (e^{x^{2}}) - \frac{\partial}{\partial y} (y)

\frac{\partial}{\partial y} (e^{x^{2}}) = 0

\frac{\partial}{\partial y} (y) = 1

= 0 - 1

Simplify

= - 1

\int sin (120 π x) d x

f (x) = 4 x^{2} - x^{3}, (1, 3)

y = - x^{2} - 2 x + 2, (- 3, - 1)

sin (x), 0

y^{^{'}} - \frac{9}{x} y = \frac{y ^{5}}{x ^{6}}

What is (\partial)/(\partial y)(e^{x^2}-y) ?
The answer to (\partial)/(\partial y)(e^{x^2}-y) is -1