What is the derivative of (e^3^{x-1}) ?

The derivative of (e^3^{x-1}) is e^{3(x-1)}*3

What is the first derivative of (e^3^{x-1}) ?

The first derivative of (e^3^{x-1}) is e^{3(x-1)}*3

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\frac{d}{d x} ((e^{3})^{x - 1})

e^{3 (x - 1)} \cdot 3

Solution steps

\frac{d}{d x} ((e^{3})^{x - 1})

Simplify

(e^{3})^{x - 1} : e^{3 (x - 1)}

= \frac{d}{d x} (e^{3 (x - 1)})

Apply the chain rule:

e^{3 (x - 1)} \frac{d}{d x} (3 (x - 1))

= e^{3 (x - 1)} \frac{d}{d x} (3 (x - 1))

\frac{d}{d x} (3 (x - 1)) = 3

= e^{3 (x - 1)} \cdot 3

\frac{d}{d x} (5 x^{8})

\int \frac{( 1 - t cos ( t ) )}{t} d t

\frac{5}{s + 1}

4 x^{4} - 4 x^{2}, 3 x^{2}, [0, 0]

n = 1 \sum \infty cos^{n} (1.6)

What is the derivative of (e^3^{x-1}) ?
The derivative of (e^3^{x-1}) is e^{3(x-1)}*3
What is the first derivative of (e^3^{x-1}) ?
The first derivative of (e^3^{x-1}) is e^{3(x-1)}*3