What is the derivative of 2+xsqrt(x) ?

The derivative of 2+xsqrt(x) is (3sqrt(x))/2

What is the first derivative of 2+xsqrt(x) ?

The first derivative of 2+xsqrt(x) is (3sqrt(x))/2

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\frac{d}{d x} (2 + x x)

\frac{3 x}{2}

Solution steps

\frac{d}{d x} (2 + x x)

Simplify

2 + x x : 2 + x^{\frac{3}{2}}

= \frac{d}{d x} (2 + x^{\frac{3}{2}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2) + \frac{d}{d x} (x^{\frac{3}{2}})

\frac{d}{d x} (2) = 0

\frac{d}{d x} (x^{\frac{3}{2}}) = \frac{3 x}{2}

= 0 + \frac{3 x}{2}

Simplify

= \frac{3 x}{2}

y = (x^{5} + 1)^{7}

\frac{d y}{d x} - y = 2 e^{x} y^{2}

\int t \cdot sin (t) d t

\frac{1}{( s + 1 ) ^{4}}

\frac{\partial}{\partial x} (y e^{6 x})

What is the derivative of 2+xsqrt(x) ?
The derivative of 2+xsqrt(x) is (3sqrt(x))/2
What is the first derivative of 2+xsqrt(x) ?
The first derivative of 2+xsqrt(x) is (3sqrt(x))/2