What is the integral of asqrt(x) ?

The integral of asqrt(x) is a 2/3 x^{3/2}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of asqrt(x)

\int a x d x

a \frac{2}{3} x^{\frac{3}{2}} + C

Solution steps

\int a x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= a \cdot \int x d x

Apply the Power Rule

: \frac{2}{3} x^{\frac{3}{2}}

= a \frac{2}{3} x^{\frac{3}{2}}

Add a constant to the solution

= a \frac{2}{3} x^{\frac{3}{2}} + C

\int x \cdot sin (\frac{nπ x}{2}) d x

\frac{\partial}{\partial y} (x^{3} + y^{3})

\int 3 x sin (x^{2}) d x

y^{^{'''}} + 6 y^{^{''}} + 9 y^{^{'}} = 0

\int_{1}^{6} \frac{2}{x - 11} d x