What is area y=x^{-3},3<= x<= 5 ?

The answer to area y=x^{-3},3<= x<= 5 is 8/225

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area y=x^{-3},3<= x<= 5

area

y = x^{- 3}, 3 \leq x \leq 5

\frac{8}{225}

Decimal

0.03555 \dots

Solution steps

Apply the area formula:

\int_{3}^{5} \frac{1}{∣ x ^{3} ∣} d x

Solve

\int_{3}^{5} \frac{1}{∣ x ^{3} ∣} d x : \frac{8}{225}

The area is:

= \frac{8}{225}

x \to 0 lim ((1 - x)^{\frac{2}{x}})

(x^{2} + 2 y^{2}) d x - (x y) d y = 0

4 - 11 x + 6 x^{2}

x 3 + y 3 - 6 x y = 0

\int \frac{1}{2 + 4 x ^{2}} d x

What is area y=x^{-3},3<= x<= 5 ?
The answer to area y=x^{-3},3<= x<= 5 is 8/225