What is (\partial)/(\partial x)(x-y^2) ?

The answer to (\partial)/(\partial x)(x-y^2) is 1

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(\partial)/(\partial x)(x-y^2)

\frac{\partial}{\partial x} (x - y^{2})

1

Solution steps

\frac{\partial}{\partial x} (x - y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x) - \frac{\partial}{\partial x} (y^{2})

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (y^{2}) = 0

= 1 - 0

Simplify

= 1

4 x^{- 2}

\frac{\partial}{\partial x} (\frac{y}{y + 4})

\int \frac{x ^{'}}{x ^{2} + 1} d x

\int x^{17} sin (x^{18}) d x

g (t) = \frac{1 - 3 t}{4 + t}

What is (\partial)/(\partial x)(x-y^2) ?
The answer to (\partial)/(\partial x)(x-y^2) is 1