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Popular >

x^'=-x/(x+1)

Solution

x^{^{'}} = - \frac{x}{x + 1}

Solution

x = W (\frac{1}{e ^{t - c_{1}}})

Solution steps

x^{'} (t) = - \frac{x}{x + 1}

Solve separable ODE:

x = W (\frac{1}{e ^{t - c_{1}}})

x = W (\frac{1}{e ^{t - c_{1}}})

Popular Examples

tangent of y=9-2x^2,(2,1)tangent of

y = 9 - 2 x^{2}, (2, 1)

integral from 0 to (3pi)/2 of cos^3(21x)

\int_{0}^{\frac{3 π}{2}} cos^{3} (21 x) d x

taylor x/(10-9x)taylor

\frac{x}{10 - 9 x}

integral of (25-x^2)^{-3/2}

\int (25 - x^{2})^{- \frac{3}{2}} d x

derivative of 10^{2x}

\frac{d}{d x} (1 0^{2 x})

Frequently Asked Questions (FAQ)

What is the solution for x^'=-x/(x+1) ?
The solution for x^'=-x/(x+1) is x=\W(1/(e^{t-c_{1)}})