What is (\partial)/(\partial y)(x^2sin(y)) ?

The answer to (\partial)/(\partial y)(x^2sin(y)) is x^2cos(y)

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(\partial)/(\partial y)(x^2sin(y))

\frac{\partial}{\partial y} (x^{2} sin (y))

x^{2} cos (y)

Solution steps

\frac{\partial}{\partial y} (x^{2} sin (y))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x^{2} \frac{\partial}{\partial y} (sin (y))

Apply the common derivative:

\frac{\partial}{\partial y} (sin (y)) = cos (y)

= x^{2} cos (y)

\int_{1}^{7} \frac{4}{x ^{2}} d x

\int_{- 64}^{1} \frac{1}{x ^{\frac{1}{3}}} d x

\int sin (4 x - 2) sin (3 x + 5) d x

4 cos (3 x), 4 - 4 cos (3 x), [0, \frac{π}{3}]

- 2 x^{3} - 4 x^{2}, at x = 1

What is (\partial)/(\partial y)(x^2sin(y)) ?
The answer to (\partial)/(\partial y)(x^2sin(y)) is x^2cos(y)