What is area 4cos(3x),4-4cos(3x),[0, pi/3 ] ?

The answer to area 4cos(3x),4-4cos(3x),[0, pi/3 ] is (4sqrt(3)pi+72)/(9sqrt(3))

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area 4cos(3x),4-4cos(3x),[0, pi/3 ]

area

4 cos (3 x), 4 - 4 cos (3 x), [0, \frac{π}{3}]

\frac{4 3 π + 72}{9 3}

Decimal

6.01506 \dots

Solution steps

Apply the area formula:

\int_{0}^{\frac{π}{3}} ∣ 4 cos (3 x) - (4 - 4 cos (3 x)) ∣ d x

Solve

\int_{0}^{\frac{π}{3}} ∣ 4 cos (3 x) - (4 - 4 cos (3 x)) ∣ d x : \frac{4 3 π + 72}{9 3}

The area is:

= \frac{4 3 π + 72}{9 3}

- 2 x^{3} - 4 x^{2}, at x = 1

\int cot^{2} (x) csc^{4} (x) d x

\frac{\partial}{\partial x} (sin (3 x + 2 y))

\frac{s}{( s ^{2} + 16 ) ^{2}}

4 y^{^{''}} + 6 y^{^{'}} + 7 y = 0

What is area 4cos(3x),4-4cos(3x),[0, pi/3 ] ?
The answer to area 4cos(3x),4-4cos(3x),[0, pi/3 ] is (4sqrt(3)pi+72)/(9sqrt(3))