What is the limit as x approaches-4 of sqrt(16-x^2) ?

The limit as x approaches-4 of sqrt(16-x^2) is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches-4 of sqrt(16-x^2)

x \to - 4 lim (16 - x^{2})

0

Solution steps

x \to - 4 lim (16 - x^{2})

Plug in the value

x = - 4

= 16 - (- 4)^{2}

Simplify

16 - (- 4)^{2} : 0

= 0

\int \frac{x}{( x - 1 ) ( x ^{2} + 2 x + 2 ) ^{2}} d x

x \to 0 + lim (\frac{2}{x})

x \frac{d y}{d x} + 8 y = e^{x^{8}}

x \to 0 + lim (1 + \frac{1}{x - 1})

\frac{d}{d x} (2 x^{2} + 8 x + 10)

What is the limit as x approaches-4 of sqrt(16-x^2) ?
The limit as x approaches-4 of sqrt(16-x^2) is 0