What is the tangent of f(x)= x/(x+1),\at x=0 ?

The tangent of f(x)= x/(x+1),\at x=0 is y=x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)= x/(x+1),\at x=0

tangent of

f (x) = \frac{x}{x + 1}, at x = 0

y = x

Solution steps

Find the tangent point:

(0, 0)

Find the slope of

f (x) = \frac{x}{x + 1} : \frac{df ( x )}{d x} = \frac{1}{( x + 1 ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 1

Find the line with slope m=

1

and passing through

(0, 0) : y = x

y = x

f (x) = (2 x - 1) (6 x - 6)^{- 1}

f (x) = \frac{x ^{2}}{x + 2}

(tan (y)) d x - (cot (x)) d y = 0

\int \frac{x - 9}{( x + 5 ) ( x - 2 )} d x

\frac{\partial}{\partial x} (2 y - x^{2} + 2)

What is the tangent of f(x)= x/(x+1),\at x=0 ?
The tangent of f(x)= x/(x+1),\at x=0 is y=x