What is (\partial)/(\partial x)(2y-x^2+2) ?

The answer to (\partial)/(\partial x)(2y-x^2+2) is -2x

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(\partial)/(\partial x)(2y-x^2+2)

\frac{\partial}{\partial x} (2 y - x^{2} + 2)

- 2 x

Solution steps

\frac{\partial}{\partial x} (2 y - x^{2} + 2)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 y) - \frac{\partial}{\partial x} (x^{2}) + \frac{\partial}{\partial x} (2)

\frac{\partial}{\partial x} (2 y) = 0

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (2) = 0

= 0 - 2 x + 0

Simplify

= - 2 x

2 e^{x - 2}

3 7 x^{6} + 8 x^{5}

sin (x) sin (y) + y^{^{'}} cos (y) = 0

\frac{d}{d x} (3 x^{2} - 6 x + 7)

\frac{x + 1}{x ^{2} + 1}

What is (\partial)/(\partial x)(2y-x^2+2) ?
The answer to (\partial)/(\partial x)(2y-x^2+2) is -2x