What is (\partial)/(\partial x)(x^2+y^2+3) ?

The answer to (\partial)/(\partial x)(x^2+y^2+3) is 2x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(x^2+y^2+3)

\frac{\partial}{\partial x} (x^{2} + y^{2} + 3)

2 x

Solution steps

\frac{\partial}{\partial x} (x^{2} + y^{2} + 3)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) + \frac{\partial}{\partial x} (y^{2}) + \frac{\partial}{\partial x} (3)

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (y^{2}) = 0

\frac{\partial}{\partial x} (3) = 0

= 2 x + 0 + 0

Simplify

= 2 x

\int arccos (8 x) d x

\frac{d}{d x} (12 x^{3} - 6 x^{2})

\frac{y}{x ^{5}}

\int 5 4 x d x

4^{2}

What is (\partial)/(\partial x)(x^2+y^2+3) ?
The answer to (\partial)/(\partial x)(x^2+y^2+3) is 2x