What is the limit as x approaches 4+of 1/(x^2-16) ?

The limit as x approaches 4+of 1/(x^2-16) is infinity

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limit as x approaches 4+of 1/(x^2-16)

x \to 4 + lim (\frac{1}{x ^{2} - 16})

\infty

Solution steps

x \to 4 + lim (\frac{1}{x ^{2} - 16})

For

x

approaching

4

from the right

, x > 4 \Rightarrow x^{2} - 16 > 0

The denominator is a positive quantity approaching 0 from the right

= \infty

\frac{d ^{2}}{d x ^{2}} (\frac{x}{x ^{2} + 4})

\int \frac{64 x ^{2} - 49}{x ^{3}} d x

(1 + y) d x + (1 - x) d y = 0

y^{^{'}} = y ln (\frac{1}{y})

\frac{d}{d x} (5 x - 3 x)

What is the limit as x approaches 4+of 1/(x^2-16) ?
The limit as x approaches 4+of 1/(x^2-16) is infinity