What is the integral of 1/(sqrt(22-x^2)) ?

The integral of 1/(sqrt(22-x^2)) is arcsin(1/(sqrt(22))x)+C

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integral of 1/(sqrt(22-x^2))

\int \frac{1}{22 - x ^{2}} d x

arcsin (\frac{1}{22} x) + C

Solution steps

\int \frac{1}{22 - x ^{2}} d x

Apply Trigonometric Substitution

: \int 1 d u

= \int 1 d u

Integral of a constant:

\int a d x = a x

= 1 \cdot u

Substitute back

u = arcsin (\frac{1}{22} x)

= 1 \cdot arcsin (\frac{1}{22} x)

Simplify

= arcsin (\frac{1}{22} x)

Add a constant to the solution

= arcsin (\frac{1}{22} x) + C

n = 0 \sum \infty 6 (\frac{1}{7})^{n}

x \to 2 - lim (\frac{x + 2}{x - 4})

n = - \infty \sum \infty 7^{2}

x \to 2 lim (\frac{3 x}{x - 4})

y^{^{''}} + 2 x = 0

What is the integral of 1/(sqrt(22-x^2)) ?
The integral of 1/(sqrt(22-x^2)) is arcsin(1/(sqrt(22))x)+C