What is the limit as x approaches 1 of x^2+2x-5/2 ?

The limit as x approaches 1 of x^2+2x-5/2 is 1/2

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limit as x approaches 1 of x^2+2x-5/2

x \to 1 lim (x^{2} + 2 x - \frac{5}{2})

\frac{1}{2}

Decimal

0.5

Solution steps

x \to 1 lim (x^{2} + 2 x - \frac{5}{2})

Plug in the value

x = 1

= 1^{2} + 2 \cdot 1 - \frac{5}{2}

Simplify

1^{2} + 2 \cdot 1 - \frac{5}{2} : \frac{1}{2}

= \frac{1}{2}

(x^{2} + 1) \frac{d y}{d x} + 4 x (y - 1) = 0, y (0) = 8

\int_{- 1}^{1} e^{y} - (y^{2} - 7) d y

\frac{d}{d x} (lo g_{9} (- (x - 4) (5 x - 2)))

\frac{\partial}{\partial y} (sin (x) y)

f (x) = \frac{x ^{5} + x ^{9}}{x}

What is the limit as x approaches 1 of x^2+2x-5/2 ?
The limit as x approaches 1 of x^2+2x-5/2 is 1/2