What is the tangent of f(x)=(6x-5)^{1/2},\at x=1 ?

The tangent of f(x)=(6x-5)^{1/2},\at x=1 is y=3x-2

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tangent of f(x)=(6x-5)^{1/2},\at x=1

tangent of

f (x) = (6 x - 5)^{\frac{1}{2}}, at x = 1

y = 3 x - 2

Solution steps

Find the tangent point:

(1, 1)

Find the slope of

f (x) = (6 x - 5)^{\frac{1}{2}} : \frac{df ( x )}{d x} = \frac{3}{( 6 x - 5 ) ^{\frac{1}{2}}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 3

Find the line with slope m=

3

and passing through

(1, 1) : y = 3 x - 2

y = 3 x - 2

\frac{d y}{d x} = 8 x^{- 9}

\frac{d}{d x} (\frac{2}{3} x^{3} - \frac{3}{4 x ^{2}})

y = sin (tan (5 x))

\int (t^{9} + 4 t) (9 t^{8} + 4) d t

\int (4 x - \frac{2}{x}) d x

What is the tangent of f(x)=(6x-5)^{1/2},\at x=1 ?
The tangent of f(x)=(6x-5)^{1/2},\at x=1 is y=3x-2