What is the tangent of y=(x^2)/(x+4),(3, 9/7) ?

The tangent of y=(x^2)/(x+4),(3, 9/7) is y= 33/49 x-36/49

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of y=(x^2)/(x+4),(3, 9/7)

tangent of

y = \frac{x ^{2}}{x + 4}, (3, \frac{9}{7})

y = \frac{33}{49} x - \frac{36}{49}

Solution steps

Find the slope of

y = \frac{x ^{2}}{x + 4} : \frac{d y}{d x} = \frac{x ^{2} + 8 x}{( x + 4 ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{33}{49}

Find the line with slope m=

\frac{33}{49}

and passing through

(3, \frac{9}{7}) : y = \frac{33}{49} x - \frac{36}{49}

y = \frac{33}{49} x - \frac{36}{49}

\int_{- 7}^{7} (49 - x^{2})^{\frac{1}{2}} d x

y^{^{'}} + x y = 6 x y^{2}

\int x^{2} + 2^{x} d x

\frac{\partial}{\partial y} (\frac{x - 2 y}{x + 2})

\int_{0}^{3} π (3 x)^{2} d x

What is the tangent of y=(x^2)/(x+4),(3, 9/7) ?
The tangent of y=(x^2)/(x+4),(3, 9/7) is y= 33/49 x-36/49