What is the integral of 5/((x-2)^2) ?

The integral of 5/((x-2)^2) is -5/(x-2)+C

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integral of 5/((x-2)^2)

\int \frac{5}{( x - 2 ) ^{2}} d x

- \frac{5}{x - 2} + C

Solution steps

\int \frac{5}{( x - 2 ) ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 5 \cdot \int \frac{1}{( x - 2 ) ^{2}} d x

Apply u-substitution

: \int \frac{1}{u ^{2}} d u

= 5 \cdot \int \frac{1}{u ^{2}} d u

Apply the Power Rule

: - \frac{1}{u}

= 5 (- \frac{1}{u})

Substitute back

u = x - 2

= 5 (- \frac{1}{x - 2})

Simplify

5 (- \frac{1}{x - 2}) : - \frac{5}{x - 2}

= - \frac{5}{x - 2}

Add a constant to the solution

= - \frac{5}{x - 2} + C

\frac{d}{d x} (2 sec (x))

y = 1 + e^{- 2 x^{2} + 8 x - 7}

x \to 0 lim (- (\frac{1}{x ^{2}}))

y^{^{'}} = 9 t y^{2}

x \to - 4 - lim (\frac{∣ x + 4 ∣}{x + 4})