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Popular >

y^'+y/t =2e^t

Solution

y^{^{'}} + \frac{y}{t} = 2 e^{t}

Solution

y = \frac{2 ( e ^{t} t - e ^{t} )}{t} + \frac{c _{1}}{t}

Solution steps

y^{'} (t) + \frac{y}{t} = 2 e^{t}

Solve linear ODE:

y = \frac{2 ( e ^{t} t - e ^{t} )}{t} + \frac{c _{1}}{t}

y = \frac{2 ( e ^{t} t - e ^{t} )}{t} + \frac{c _{1}}{t}

Graph

Popular Examples

derivative of sqrt(x^2+6x)derivative of

x^{2} + 6 x

y^'= 2/(3x)y+(2x)/y

y^{^{'}} = \frac{2}{3 x} y + \frac{2 x}{y}

normal of y=x^2-5x,(7,14)normal of

y = x^{2} - 5 x, (7, 14)

limit as x approaches-infinity of x^3+2

x \to - \infty lim (x^{3} + 2)

derivative of sqrt(2x)+sqrt(y)derivative of

2 x + y

Frequently Asked Questions (FAQ)

What is the solution for y^'+y/t =2e^t ?
The solution for y^'+y/t =2e^t is y=(2(e^tt-e^t))/t+(c_{1})/t