What is the derivative of 5/x ln(x) ?

The derivative of 5/x ln(x) is (5(-ln(x)+1))/(x^2)

What is the first derivative of 5/x ln(x) ?

The first derivative of 5/x ln(x) is (5(-ln(x)+1))/(x^2)

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\frac{d}{d x} (\frac{5}{x} ln (x))

\frac{5 ( - ln ( x ) + 1 )}{x ^{2}}

Solution steps

\frac{d}{d x} (\frac{5}{x} ln (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 5 \frac{d}{d x} (\frac{1}{x} ln (x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = \frac{1}{x}, g = ln (x)

= 5 (\frac{d}{d x} (\frac{1}{x}) ln (x) + \frac{d}{d x} (ln (x)) \frac{1}{x})

\frac{d}{d x} (\frac{1}{x}) = - \frac{1}{x ^{2}}

\frac{d}{d x} (ln (x)) = \frac{1}{x}

= 5 ((- \frac{1}{x ^{2}}) ln (x) + \frac{1}{x} \cdot \frac{1}{x})

Simplify

5 ((- \frac{1}{x ^{2}}) ln (x) + \frac{1}{x} \cdot \frac{1}{x}) : \frac{5 ( - ln ( x ) + 1 )}{x ^{2}}

= \frac{5 ( - ln ( x ) + 1 )}{x ^{2}}

(tan (3 x))^{^{'}}

\int_{1}^{2} (1 - x^{2}) - (3 - 3 x) d x

\frac{d x}{d t} = x^{2} - 6 x + 14

f (x) = 2 x^{4} + x^{3} - x^{2} + 4

\int_{0}^{x} 1 + 9 t d t

What is the derivative of 5/x ln(x) ?
The derivative of 5/x ln(x) is (5(-ln(x)+1))/(x^2)
What is the first derivative of 5/x ln(x) ?
The first derivative of 5/x ln(x) is (5(-ln(x)+1))/(x^2)