What is the first (tan(3x))^' ?

The first (tan(3x))^' is sec^2(3x)*3

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(tan(3x))^'

(tan (3 x))^{^{'}}

sec^{2} (3 x) \cdot 3

Solution steps

(tan (3 x))^{'}

Apply the chain rule:

sec^{2} (3 x) (3 x)^{'}

= sec^{2} (3 x) (3 x)^{'}

(3 x)^{'} = 3

= sec^{2} (3 x) \cdot 3

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