What is the solution for (x^2-3y^2)dx+2xydy=0 ?

The solution for (x^2-3y^2)dx+2xydy=0 is y=xsqrt(1+c_{1)x},y=-xsqrt(1+c_{1)x}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x^2-3y^2)dx+2xydy=0

(x^{2} - 3 y^{2}) d x + 2 x y d y = 0

y = x 1 + c_{1} x, y = - x 1 + c_{1} x

Solution steps

(x^{2} - 3 y^{2}) d x + 2 x y d y = 0

Solve Bernoulli ODE:

y = x 1 + c_{1} x, y = - x 1 + c_{1} x

y = x 1 + c_{1} x, y = - x 1 + c_{1} x

x \to π lim (sin (\frac{11}{6} x))

\int sin^{5} (7 x) d x

\frac{d y}{d x} = 32 x^{3} y^{3}

x \to 0 lim ((1 - \frac{1}{2 x})^{x})

\frac{d}{d y} (y e^{x} + 2 e^{x} + y^{2})

What is the solution for (x^2-3y^2)dx+2xydy=0 ?
The solution for (x^2-3y^2)dx+2xydy=0 is y=xsqrt(1+c_{1)x},y=-xsqrt(1+c_{1)x}