What is area (x+5)^2, 1/3 x+3,-10,-5 ?

The answer to area (x+5)^2, 1/3 x+3,-10,-5 is 245/6

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area (x+5)^2, 1/3 x+3,-10,-5

area

(x + 5)^{2}, \frac{1}{3} x + 3, - 10, - 5

\frac{245}{6}

Decimal

40.83333 \dots

Solution steps

Apply the area formula:

\int_{- 10}^{- 5} (x + 5)^{2} - (\frac{1}{3} x + 3) d x

Solve

\int_{- 10}^{- 5} (x + 5)^{2} - (\frac{1}{3} x + 3) d x : \frac{245}{6}

The area is:

= \frac{245}{6}

\int (1 - x^{9}) d x

\int \frac{1}{- x ^{2} - 10 x - 21} d x

(x + 4) (x - 5)^{2}

\frac{s + 1}{( s + 2 ) ( s + 6 ) ^{2}}

f (x) = x^{3} - 2 x + 7, at x = - 2

What is area (x+5)^2, 1/3 x+3,-10,-5 ?
The answer to area (x+5)^2, 1/3 x+3,-10,-5 is 245/6