What is the integral from 0 to pi of 9sin(x) ?

The integral from 0 to pi of 9sin(x) is 18

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integral from 0 to pi of 9sin(x)

\int_{0}^{π} 9 sin (x) d x

18

Solution steps

\int_{0}^{π} 9 sin (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 9 \cdot \int_{0}^{π} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= 9 [- cos (x)]_{0}^{π}

Compute the boundaries:

2

= 9 \cdot 2

Simplify

= 18

\frac{d}{d x} (\frac{x ^{12}}{x ^{2}})

y^{^{'}} = x^{2} \cdot (1 + y)

n = 1 \sum \infty n (\frac{1}{2})^{n}

\int cos (3 x) e^{2 x} d x

f (x) = x^{5} e^{8 x}

What is the integral from 0 to pi of 9sin(x) ?
The integral from 0 to pi of 9sin(x) is 18