What is the derivative of f(x)= 1/((2x+1)^2) ?

The derivative of f(x)= 1/((2x+1)^2) is -4/((2x+1)^3)

What is the first derivative of f(x)= 1/((2x+1)^2) ?

The first derivative of f(x)= 1/((2x+1)^2) is -4/((2x+1)^3)

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derivative of

f (x) = \frac{1}{( 2 x + 1 ) ^{2}}

- \frac{4}{( 2 x + 1 ) ^{3}}

Solution steps

\frac{d}{d x} (\frac{1}{( 2 x + 1 ) ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((2 x + 1)^{- 2})

Apply the chain rule:

- \frac{2}{( 2 x + 1 ) ^{3}} \frac{d}{d x} (2 x + 1)

= - \frac{2}{( 2 x + 1 ) ^{3}} \frac{d}{d x} (2 x + 1)

\frac{d}{d x} (2 x + 1) = 2

= - \frac{2}{( 2 x + 1 ) ^{3}} \cdot 2

Simplify

- \frac{2}{( 2 x + 1 ) ^{3}} \cdot 2 : - \frac{4}{( 2 x + 1 ) ^{3}}

= - \frac{4}{( 2 x + 1 ) ^{3}}

\frac{d y}{d x} = \frac{7 x + 2 y}{7 x + 2 y + 2}

f (x) = 2 - 7 x, (- 2, 4)

\frac{d}{d x} (∣ cos (x) ∣)

(y^{3} - 1) e^{x} d x + 3 y^{2} (e^{x} + 1) d y = 0, y (0) = - 2

\int 3 x^{2} + 5 d x

What is the derivative of f(x)= 1/((2x+1)^2) ?
The derivative of f(x)= 1/((2x+1)^2) is -4/((2x+1)^3)
What is the first derivative of f(x)= 1/((2x+1)^2) ?
The first derivative of f(x)= 1/((2x+1)^2) is -4/((2x+1)^3)