What is the integral from 5 to 20 of (x^2x) ?

The integral from 5 to 20 of (x^2x) is 159375/4

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integral from 5 to 20 of (x^2x)

\int_{5}^{20} (x^{2} x) d x

\frac{159375}{4}

Decimal

39843.75

Solution steps

\int_{5}^{20} x^{2} x d x

Simplify

x^{2} x : x^{3}

= \int_{5}^{20} x^{3} d x

Apply the Power Rule

: [\frac{x ^{4}}{4}]_{5}^{20}

= [\frac{x ^{4}}{4}]_{5}^{20}

Compute the boundaries:

\frac{159375}{4}

= \frac{159375}{4}

x \to 0 lim (\frac{5 x}{sin ( x )})

\frac{d}{d x} (lo g_{10} (cos (x)))

n = 0 \sum \infty n^{3} (x - 5)^{n}

\frac{d y}{d x} 7 x^{3} + 7 y^{3} - 3 x y = 0

\frac{d}{d x} (\frac{5 x - 7}{6 x - 9})

What is the integral from 5 to 20 of (x^2x) ?
The integral from 5 to 20 of (x^2x) is 159375/4