What is the integral of (e^{1+ln(x)})/x ?

The integral of (e^{1+ln(x)})/x is ex+C

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integral of (e^{1+ln(x)})/x

\int \frac{e ^{1 + l n (x)}}{x} d x

e x + C

Solution steps

\int \frac{e ^{1 + l n (x)}}{x} d x

\frac{e ^{1 + l n (x)}}{x} = e

= \int e d x

Integral of a constant:

\int a d x = a x

= e x

Add a constant to the solution

= e x + C

y^{^{'}} = \frac{y ^{2} + 1}{x}

x \to \infty lim (I n (x))

f (x) = \frac{x ^{2} - 4 x}{x + 1}

\frac{\partial}{\partial x} (3 x^{3} + 4 x^{2} y - y^{3})

x \to + 0 + lim (arctan (ln (x)))

What is the integral of (e^{1+ln(x)})/x ?
The integral of (e^{1+ln(x)})/x is ex+C