What is the d/(dy)((y^3)/(21)+7/(4y)) ?

The d/(dy)((y^3)/(21)+7/(4y)) is (y^2)/7-7/(4y^2)

What is the first d/(dy)((y^3)/(21)+7/(4y)) ?

The first d/(dy)((y^3)/(21)+7/(4y)) is (y^2)/7-7/(4y^2)

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\frac{d}{d y} (\frac{y ^{3}}{21} + \frac{7}{4 y})

\frac{y ^{2}}{7} - \frac{7}{4 y ^{2}}

Solution steps

\frac{d}{d y} (\frac{y ^{3}}{21} + \frac{7}{4 y})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d y} (\frac{y ^{3}}{21}) + \frac{d}{d y} (\frac{7}{4 y})

\frac{d}{d y} (\frac{y ^{3}}{21}) = \frac{y ^{2}}{7}

\frac{d}{d y} (\frac{7}{4 y}) = - \frac{7}{4 y ^{2}}

= \frac{y ^{2}}{7} - \frac{7}{4 y ^{2}}

f (x) = 8 x + ln (x^{2})

\int (5 x^{3} + 6)^{4} x^{2} d x

y^{^{'}} - y = 5 t e^{2 t}, y (0) = 1

n = 0 \sum \infty (1.075)^{n}

y = x + 1, (0, 2)

What is the d/(dy)((y^3)/(21)+7/(4y)) ?
The d/(dy)((y^3)/(21)+7/(4y)) is (y^2)/7-7/(4y^2)
What is the first d/(dy)((y^3)/(21)+7/(4y)) ?
The first d/(dy)((y^3)/(21)+7/(4y)) is (y^2)/7-7/(4y^2)