What is the d/(dθ)(2/(6cos(θ)+7sin(θ))) ?

The d/(dθ)(2/(6cos(θ)+7sin(θ))) is -(2(-6sin(θ)+7cos(θ)))/((6cos(θ)+7sin(θ))^2)

What is the first d/(dθ)(2/(6cos(θ)+7sin(θ))) ?

The first d/(dθ)(2/(6cos(θ)+7sin(θ))) is -(2(-6sin(θ)+7cos(θ)))/((6cos(θ)+7sin(θ))^2)

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\frac{d}{d θ} (\frac{2}{6 cos ( θ ) + 7 sin ( θ )})

- \frac{2 ( - 6 sin ( θ ) + 7 cos ( θ ) )}{( 6 cos ( θ ) + 7 sin ( θ ) ) ^{2}}

Solution steps

\frac{d}{d θ} (\frac{2}{6 cos ( θ ) + 7 sin ( θ )})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d θ} (\frac{1}{6 cos ( θ ) + 7 sin ( θ )})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 2 \frac{d}{d θ} ((6 cos (θ) + 7 sin (θ))^{- 1})

Apply the chain rule:

- \frac{1}{( 6 cos ( θ ) + 7 sin ( θ ) ) ^{2}} \frac{d}{d θ} (6 cos (θ) + 7 sin (θ))

= - \frac{1}{( 6 cos ( θ ) + 7 sin ( θ ) ) ^{2}} \frac{d}{d θ} (6 cos (θ) + 7 sin (θ))

\frac{d}{d θ} (6 cos (θ) + 7 sin (θ)) = - 6 sin (θ) + 7 cos (θ)

= 2 (- \frac{1}{( 6 cos ( θ ) + 7 sin ( θ ) ) ^{2}} (- 6 sin (θ) + 7 cos (θ)))

Simplify

2 (- \frac{1}{( 6 cos ( θ ) + 7 sin ( θ ) ) ^{2}} (- 6 sin (θ) + 7 cos (θ))) : - \frac{2 ( - 6 sin ( θ ) + 7 cos ( θ ) )}{( 6 cos ( θ ) + 7 sin ( θ ) ) ^{2}}

= - \frac{2 ( - 6 sin ( θ ) + 7 cos ( θ ) )}{( 6 cos ( θ ) + 7 sin ( θ ) ) ^{2}}

\int_{0}^{3} (\frac{1}{x ^{2}}) d x

x \to 2 lim (x^{2} - 8)

\frac{d}{d x} (- \frac{1}{4} x^{- \frac{3}{2}})

\frac{d}{d x} (\frac{x ^{2} - 3 x + 2}{- x ^{2} - 4 x + 4})

3 x^{2} + 4

What is the d/(dθ)(2/(6cos(θ)+7sin(θ))) ?
The d/(dθ)(2/(6cos(θ)+7sin(θ))) is -(2(-6sin(θ)+7cos(θ)))/((6cos(θ)+7sin(θ))^2)
What is the first d/(dθ)(2/(6cos(θ)+7sin(θ))) ?
The first d/(dθ)(2/(6cos(θ)+7sin(θ))) is -(2(-6sin(θ)+7cos(θ)))/((6cos(θ)+7sin(θ))^2)