What is the tangent of f(x)=csc^2(x),(pi/2 ,1) ?

The tangent of f(x)=csc^2(x),(pi/2 ,1) is y=1

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tangent of f(x)=csc^2(x),(pi/2 ,1)

tangent of

f (x) = csc^{2} (x), (\frac{π}{2}, 1)

y = 1

Solution steps

Find the slope of

f (x) = csc^{2} (x) : \frac{df ( x )}{d x} = - 2 csc^{2} (x) cot (x)

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 0

Find the line with slope m=

0

and passing through

(\frac{π}{2}, 1) : y = 1

y = 1

\int \frac{1}{( x ^{2} + 16 ) ^{2}} d x

(- 2.7) (2.3)

\int_{0}^{1} x e^{2 x^{2}} d x

n = 1 \sum \infty p (1 - p)^{2 n}

\frac{d y}{d x} = \frac{y ^{2} + 1}{x ^{2} + 1}, y (0) = 1

What is the tangent of f(x)=csc^2(x),(pi/2 ,1) ?
The tangent of f(x)=csc^2(x),(pi/2 ,1) is y=1