What is the solution for (dy)/(dx)=(y^2+1)/(x^2+1),y(0)=1 ?

The solution for (dy)/(dx)=(y^2+1)/(x^2+1),y(0)=1 is y=tan(arctan(x)+pi/4)

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(dy)/(dx)=(y^2+1)/(x^2+1),y(0)=1

\frac{d y}{d x} = \frac{y ^{2} + 1}{x ^{2} + 1}, y (0) = 1

y = tan (arctan (x) + \frac{π}{4})

Solution steps

\frac{d y}{d x} = \frac{y ^{2} + 1}{x ^{2} + 1}

Solve separable ODE:

y = tan (arctan (x) + \frac{π}{4})

y = tan (arctan (x) + \frac{π}{4})

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f (x) = 5 lo g_{10} (4 x^{2})

\frac{d}{d x} (sin^{4} (2 x) cos^{4} (3 x))

\frac{384 x}{x ^{2} + 289}

2 x^{2} + 3 x

What is the solution for (dy)/(dx)=(y^2+1)/(x^2+1),y(0)=1 ?
The solution for (dy)/(dx)=(y^2+1)/(x^2+1),y(0)=1 is y=tan(arctan(x)+pi/4)