What is the tangent of 2x^2+3x ?

The tangent of 2x^2+3x is y=(4a_{0}+3)x-2a_{0}^2

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tangent of 2x^2+3x

tangent of

2 x^{2} + 3 x

y = (4 a_{0} + 3) x - 2 a_{0}^{2}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 2 a_{0}^{2} + 3 a_{0})

Find the slope of

y = 2 x^{2} + 3 x : \frac{d y}{d x} = 4 x + 3

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 4 a_{0} + 3

Find the line with slope m=

4 a_{0} + 3

and passing through

(a_{0}, 2 a_{0}^{2} + 3 a_{0}) : y = (4 a_{0} + 3) x - 2 a_{0}^{2}

y = (4 a_{0} + 3) x - 2 a_{0}^{2}

\int_{0}^{1.2} (1 - \frac{y}{2}) d y

\frac{d}{d x} (\frac{u}{x})

x \to \infty lim (x^{x})

\int \frac{2}{x x ^{2} - 4} d x

\int_{3}^{4} - lo g_{9} (x) d x

What is the tangent of 2x^2+3x ?
The tangent of 2x^2+3x is y=(4a_{0}+3)x-2a_{0}^2