What is the derivative of \sqrt[3]{x}+6sqrt(x^3) ?

The derivative of \sqrt[3]{x}+6sqrt(x^3) is 1/(3x^{2/3)}+9sqrt(x)

What is the first derivative of \sqrt[3]{x}+6sqrt(x^3) ?

The first derivative of \sqrt[3]{x}+6sqrt(x^3) is 1/(3x^{2/3)}+9sqrt(x)

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derivative of

3 x + 6 x^{3}

\frac{1}{3 x ^{\frac{2}{3}}} + 9 x

Solution steps

\frac{d}{d x} (3 x + 6 x^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x) + \frac{d}{d x} (6 x^{3})

\frac{d}{d x} (3 x) = \frac{1}{3 x ^{\frac{2}{3}}}

\frac{d}{d x} (6 x^{3}) = 9 x

= \frac{1}{3 x ^{\frac{2}{3}}} + 9 x

\frac{d}{d x} (2^{x + 1})

\int e^{x} e^{2 x} + 4 d x

\int cos^{4} (x) \cdot sin^{3} (x) d x

\frac{d}{d x} (x^{2} + sin (2 x))

\frac{d}{d x} (\frac{3 ( 2 x + 1 )}{6 x + 6 x ^{2}})

What is the derivative of \sqrt[3]{x}+6sqrt(x^3) ?
The derivative of \sqrt[3]{x}+6sqrt(x^3) is 1/(3x^{2/3)}+9sqrt(x)
What is the first derivative of \sqrt[3]{x}+6sqrt(x^3) ?
The first derivative of \sqrt[3]{x}+6sqrt(x^3) is 1/(3x^{2/3)}+9sqrt(x)