What is (\partial)/(\partial x)(x^2+4y^2) ?

The answer to (\partial)/(\partial x)(x^2+4y^2) is 2x

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(\partial)/(\partial x)(x^2+4y^2)

\frac{\partial}{\partial x} (x^{2} + 4 y^{2})

2 x

Solution steps

\frac{\partial}{\partial x} (x^{2} + 4 y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) + \frac{\partial}{\partial x} (4 y^{2})

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (4 y^{2}) = 0

= 2 x + 0

Simplify

= 2 x

\int sin (x) cos (x) x d x

x \to 1 + lim (\frac{5 x + 6}{x - 1})

x = - 5, x = 1, y = 7 x, y = x^{2} - 8

t^{3} + 1 t, at t = 1

\frac{\partial}{\partial u} (3 y uxu v^{3} - 2)

What is (\partial)/(\partial x)(x^2+4y^2) ?
The answer to (\partial)/(\partial x)(x^2+4y^2) is 2x